MathTest - Revision history

Admin at 05:31, 11 May 2011

2011-05-11T05:31:07Z

← Older revision		Revision as of 05:31, 11 May 2011
Line 1:		Line 1:
	A much more detailed version of this is here: http://meta.wikimedia.org/wiki/Help:Displaying_a_formula		{{fmbox
			\|text=A much more detailed version of this is here: http://meta.wikimedia.org/wiki/Help:Displaying_a_formula
	~~{{fmbox \| text = Some text.~~}}		}}

2011-05-04T23:02:22Z

@@ Line 70: / Line 70: @@
 x + 7z &=& 8y^2 + 2y - 5
 \end{array}
 </math>

2011-04-10T19:08:58Z

2011-03-16T10:36:48Z

← Older revision		Revision as of 10:36, 16 March 2011
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	\|		\|
	<pre>		<pre>
			<math>
	\operatorname{erfc}(x) =		\operatorname{erfc}(x) =
	\frac{2}{\sqrt{\pi}} \int_x^{\infty} e^{-t^2}\,dt =		\frac{2}{\sqrt{\pi}} \int_x^{\infty} e^{-t^2}\,dt =
	\frac{e^{-x^2}}{x\sqrt{\pi}}\sum_{n=0}^\infty (-1)^n \frac{(2n)!}{n!(2x)^{2n}}		\frac{e^{-x^2}}{x\sqrt{\pi}}\sum_{n=0}^\infty (-1)^n \frac{(2n)!}{n!(2x)^{2n}}
			</math>
	</pre>		</pre>
	\|		\|
Line 32:		Line 34:
	\|		\|
	<pre>		<pre>
			<math>
	\begin{align}		\begin{align}
	y &=& x + 2 \\		y &=& x + 2 \\
	5x + 7z &=& 8y^2 + 2y - 5		5x + 7z &=& 8y^2 + 2y - 5
	\end{align}		\end{align}
			</math>
	</pre>		</pre>
	\|		\|
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	\|		\|
	<pre>		<pre>
			<math>
	\begin{array}{rcl}		\begin{array}{rcl}
	y & = & x + 2 \\		y & = & x + 2 \\
	5x + 7z &=& 8y^2 + 2y - 5		5x + 7z &=& 8y^2 + 2y - 5
	\end{array}		\end{array}
			</math>
	</pre>		</pre>
	\|		\|

2010-11-03T22:23:06Z

← Older revision		Revision as of 22:23, 3 November 2010
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	A much more detailed version of this is here: http://meta.wikimedia.org/wiki/Help:Displaying_a_formula		A much more detailed version of this is here: http://meta.wikimedia.org/wiki/Help:Displaying_a_formula

			{{fmbox \| text = Some text.}}

2010-10-22T00:20:50Z

← Older revision		Revision as of 00:20, 22 October 2010
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			{\|border=1 width=100%

			\|colspan="2"\|
			<br />
	A single equation:		A single equation:

	{\|~~border=1 width=100%~~		\|-
	\|		\|
	<pre>		<pre>
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	\frac{e^{-x^2}}{x\sqrt{\pi}}\sum_{n=0}^\infty (-1)^n \frac{(2n)!}{n!(2x)^{2n}}		\frac{e^{-x^2}}{x\sqrt{\pi}}\sum_{n=0}^\infty (-1)^n \frac{(2n)!}{n!(2x)^{2n}}
	</math>		</math>
	\|}

			\|-
			\|colspan="2"\|
			<br />
	Multiple-line equation (default alignments):		Multiple-line equation (default alignments):

	{\|~~border=1 width=100%~~		\|-
	\|		\|
	<pre>		<pre>
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	\end{align}		\end{align}
	</math>		</math>
	\|}


			\|-
			\|colspan="2"\|
			<br />
	Multiple-line equation (user-set alignments, Right-Center-Left):		Multiple-line equation (user-set alignments, Right-Center-Left):

	{\|~~border=1 width=100%~~		\|-
	\|		\|
	<pre>		<pre>
Line 56:		Line 63:
	\end{array}		\end{array}
	</math>		</math>

	\|}		\|}

2010-10-21T22:36:03Z

← Older revision		Revision as of 22:36, 21 October 2010
Line 1:		Line 1:
			A much more detailed version of this is here: http://meta.wikimedia.org/wiki/Help:Displaying_a_formula


	A single equation:		A single equation:

2010-10-21T22:35:19Z

← Older revision		Revision as of 22:35, 21 October 2010
Line 1:		Line 1:
	A single equation:		A single equation:

			{\|border=1 width=100%
			\|
			<pre>
			\operatorname{erfc}(x) =
			\frac{2}{\sqrt{\pi}} \int_x^{\infty} e^{-t^2}\,dt =
			\frac{e^{-x^2}}{x\sqrt{\pi}}\sum_{n=0}^\infty (-1)^n \frac{(2n)!}{n!(2x)^{2n}}
			</pre>
			\|
	<math>		<math>
	\operatorname{erfc}(x) =		\operatorname{erfc}(x) =
	\frac{2}{\sqrt{\pi}} \int_x^{\infty} e^{-t^2}\,dt =		\frac{2}{\sqrt{\pi}} \int_x^{\infty} e^{-t^2}\,dt =
	\frac{e^{-x^2}}{x\sqrt{\pi}}\sum_{n=0}^\infty (-1)^n \frac{(2n)!}{n!(2x)^{2n}}		\frac{e^{-x^2}}{x\sqrt{\pi}}\sum_{n=0}^\infty (-1)^n \frac{(2n)!}{n!(2x)^{2n}}
	</math>		</math>
			\|}

	Multiple-line equation (default alignments):		Multiple-line equation (default alignments):

2010-10-21T20:52:51Z

@@ Line 1: / Line 1: @@
-This is a math test:
+A single equation:
 <math>
@@ Line 8: / Line 7: @@
 </math>
 <math>
-y = x + 2
+\begin{array}{rcl}
 </math>

2010-09-29T16:41:40Z

← Older revision		Revision as of 16:41, 29 September 2010
Line 6:		Line 6:
	\frac{2}{\sqrt{\pi}} \int_x^{\infty} e^{-t^2}\,dt =		\frac{2}{\sqrt{\pi}} \int_x^{\infty} e^{-t^2}\,dt =
	\frac{e^{-x^2}}{x\sqrt{\pi}}\sum_{n=0}^\infty (-1)^n \frac{(2n)!}{n!(2x)^{2n}}		\frac{e^{-x^2}}{x\sqrt{\pi}}\sum_{n=0}^\infty (-1)^n \frac{(2n)!}{n!(2x)^{2n}}
	</math>		</math>

			<math>
			y = x + 2
			</math>