Tripos Bot: Difference between revisions
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===original notes=== | |||
Code: https://charlesreid1.com:3000/charlesreid1/tripos-bot | Code: https://charlesreid1.com:3000/charlesreid1/tripos-bot | ||
| Line 13: | Line 15: | ||
This should round it out: | This should round it out: | ||
* https://books.google.com/books?id=awMAAAAAQAAJ&printsec=frontcover&dq=cambridge+mathematics+tripos&hl=en&sa=X&ved=0ahUKEwiY85ufqsjYAhUL_4MKHWBtALA4FBDoAQgnMAA#v=onepage&q=cambridge%20mathematics%20tripos&f=false | * https://books.google.com/books?id=awMAAAAAQAAJ&printsec=frontcover&dq=cambridge+mathematics+tripos&hl=en&sa=X&ved=0ahUKEwiY85ufqsjYAhUL_4MKHWBtALA4FBDoAQgnMAA#v=onepage&q=cambridge%20mathematics%20tripos&f=false | ||
===latex problems=== | |||
this just got a whole lot easier... Gutenberg offers a TeX version of Hardy's Course of Pure Mathematics: | |||
https://www.gutenberg.org/ebooks/38769 | |||
This means the problems appear like this: | |||
<pre> | |||
\Item{18.} If $a$, $b$, $x$, $y$ are rational numbers such that | |||
\[ | |||
(ay - bx)^{2} + 4(a - x)(b - y) = 0, | |||
\] | |||
then either (i)~$x = a$, $y = b$ or (ii)~$1 - ab$ and~$1 - xy$ are squares of rational | |||
numbers. \MathTrip{1903.} | |||
</pre> | |||
===planning=== | |||
===flags=== | |||
[[Category:2018]] | [[Category:2018]] | ||
Revision as of 00:11, 12 January 2018
original notes
Code: https://charlesreid1.com:3000/charlesreid1/tripos-bot
Tripos bot:
- Tweets one problem per week
- One image per problem
- Images come from Latex, rendered with "index card" class, converted to image (one-time, offline)
- Depending on number of Tripos problems: can definitely find 52, but not sure if I can find 365
- If we can find 365, then one per day...
Hardy's Course of Pure Mathematics:
- Around 210 Tripos problems - still need another 150 or so.
This should round it out:
latex problems
this just got a whole lot easier... Gutenberg offers a TeX version of Hardy's Course of Pure Mathematics:
https://www.gutenberg.org/ebooks/38769
This means the problems appear like this:
\Item{18.} If $a$, $b$, $x$, $y$ are rational numbers such that
\[
(ay - bx)^{2} + 4(a - x)(b - y) = 0,
\]
then either (i)~$x = a$, $y = b$ or (ii)~$1 - ab$ and~$1 - xy$ are squares of rational
numbers. \MathTrip{1903.}