ProbabilityDiscussion: Difference between revisions
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Statistical Inference (Casella and Berger) | Statistical Inference (Casella and Berger) | ||
[[wikipedia:Set (mathematics]] | [[wikipedia:Set (mathematics)]] | ||
[[wikipedia:Probability interpretations]] | [[wikipedia:Probability interpretations]] | ||
Revision as of 19:55, 7 October 2010
October 7, 2010
Statistical Inference (Casella and Berger)
wikipedia:Probability interpretations
http://en.wikipedia.org/wiki/Set_%28mathematics%29
http://en.wikipedia.org/wiki/Probability_interpretations
Set Theory:
Union - combination of two sets
Complement - everything that's not in A
Empty - no elements
Definitions:
experiment - any activity generating observable results
outcome - result of experiment (IMPORTANT TO KEEP STRAIGHT! don't confuse events and outcomes)
trial - single performance of experiment
sample space - set of all possible outcomes
countable/uncountable: - countable = one-to-one correspondence (e.g. 1/n) - uncountable = no one-to-one correspondence can be made -- infinite loop: you can do an infinite loop, but still count it -- flipping a coin: countable; temperature: uncountable
event - any subset of the sample space
Example:
experiment - roll a dice outcome - 1, or 2, or 3, or 4, or 5, or 6 trial - one roll of the dice COUNTABLE sample space - {1,2,3,4,5,6} event - may be {1}, or {1,2,3}, etc...
Operators:
Union, empty set, complement, intersection
Commutative:
Associative:
Distributive:
DeMorgan's Law:
Call a set abnormal if it can be put into itself (otherwise it's normal)
Example: the set of all squares is not itself square, so it is not a member of the set of squares The complimentary set, containing all non-squares, is itself not a square, so is normal
Consider the set of all normal sets Is it normal or abnormal? If it were normal, it would be contained in itself, and would therefore be abnormal If it were abnormal, it would not be contained in itself, and would therefore be normal
You can resolve this using more rigorous set theory...
More Definitions:
Disjoint ("set" term) / mutually exclusive ("probability" term) - if the intersection of two sets is the null set, they are mutually exclusive
Partition - take a group of sets; if the union of these sets is the sample sapce, and they are mutually exclusive, this is a partition
Distinction between probability theory that has a physical meaning (and is therefore "contaminated" by intuition) and a more abstract probability theory that doesn't have a corresponding physical meaning
Axiomatic probability theory (Komolgorov)
A probability is a function that follows 3 axioms:
Sample space $ S $
(The domain) $ \sigma $-algebra $ \mathfrak{B} $ (means the set is fully consistent)
Function P -> probability over the domain $ \mathfrak{B} $
1. $ P(A) \geq 0 $ for all $ A \in \mathfrak{B} $
2. $ P(S) = 1 $
3. If $ A \in \mathfrak{B} $ and $ B \in \mathfrak{B} $ are disjoint, then $ P(A \bigcup B) = P(A) + P(B) $
In other words, $ P( \bigcup_{i=1}^{\infty} = \sum_{l=1}^{\infty} P(A_{i}) $
This is a mathematician's viewpoint: a clean definition, as long as we follow these rules, the function is a probability.
What is the probability of the null set?
Create a partition: $ S = {S, \emptyset} $
The probability of the sample space is $ P(S) = 1 $
So $ P(\emptyset) = 1 - P(S) = 0 $
$ P(A) = 1 $
$ P(A^c) = 1-P(A) $
If $ A \subset B $ then $ P(A) \leq P(B) $
The size of the set is directly related to the probability...
Another way to do this is using measure theory (another route, besides rigorous set theory, that leads to probability theory)
[wikipedia:Measure theory]
[wikipedia:Sigma-algebra]
Bonferroni's inequality: $ P(A \bigcap B) \geq P(A) + P(B) - 1 $
Reading Assignment Discussion
Classical Definition of Probability (Laplace, 1812)
"If a random experiment can result in $ N $ mutually exclusive and equally likely outcomes and if $ N_A $ of these outcomes result in the occurrence of the event $ A $, the probability of $ A $ is defined by $ P(A) = P{A} = {N_A \over N} $."
Example: rolling a dice
Event A might be how many times we roll a 1... or how many times we roll a 1 or a 2...
What if one side of the dice is weighted to favor 5? This definition doesn't work... No mathematical proof to show that the outcomes were mutually exclusive and equally likely.
Frequency
This is the limit, as the number of experimental trials performed (trials must be performed under "identical" conditions) goes to infinity, of the number of outcomes of the event of interest $ N_A $:
$ P(A) = lim_{n \rightarrow \infty} {N_A \over N} $
Limitations:
- can never actually perform an infinite number of trials
- what does "identical" mean? e.g. if you're performing a turbulence experiment, how can you initialize everthing the exact same way?
- (Tony): what's your infinity?
- (Sean): whatever it is, it's not finite
Probability can be seen as lack of information (e.g. fluid mechanics is deterministic, so we could describe it if we know the state perfectly - we use probability to fill in/make up for the lack of knowledge)
Quantum theory: in two-split experiment, the very state of nature is random and needs to be defined using probability
Probability of an outcome in the future: judging confidence based on prior experience... statement of confidence
Bayesian vs. fequentist