MathTest: Difference between revisions
From charlesreid1
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$x \implies y$ | $x \implies y$ | ||
<math> | |||
\operatorname{erfc}(x) = | |||
\frac{2}{\sqrt{\pi}} \int_x^{\infty} e^{-t^2}\,dt = | |||
\frac{e^{-x^2}}{x\sqrt{\pi}}\sum_{n=0}^\infty (-1)^n \frac{(2n)!}{n!(2x)^{2n}} | |||
</math> | |||
Revision as of 07:22, 29 September 2010
This is a math test:
$x + y$
$x \implies y$
$ \operatorname{erfc}(x) = \frac{2}{\sqrt{\pi}} \int_x^{\infty} e^{-t^2}\,dt = \frac{e^{-x^2}}{x\sqrt{\pi}}\sum_{n=0}^\infty (-1)^n \frac{(2n)!}{n!(2x)^{2n}} $