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<math>
<math>
\dfrac{partial P}{\partial V} \bigg|_{T=T_c,V=V_c} = 0
\dfrac{\partial P}{\partial V} \bigg|_{T=T_c,V=V_c} = 0
</math>
</math>


Line 18: Line 18:


<math>
<math>
\dfrac{partial^2 P}{\partial V^2} \bigg|_{T=T_c,V=V_c} = 0
\dfrac{\partial^2 P}{\partial V^2} \bigg|_{T=T_c,V=V_c} = 0
</math>
</math>

Revision as of 03:10, 22 May 2016

The Van Der Waal equation for a gas accounts for non-ideal behavior:

$ (P + \dfrac{a}{V^2})(V-b) = kT $

where P is the pressure, V is the molar volume (volume of a certain number of moles), a and b are constants that depend on the molecules, k is the Boltzmann constant, and T is temperature.

Now the critical points can be found: https://www.youtube.com/watch?v=VjVQxzxxLVw

Critical point is the saddle point of the above equation, and is defined as the point where:

$ \dfrac{\partial P}{\partial V} \bigg|_{T=T_c,V=V_c} = 0 $

and

$ \dfrac{\partial^2 P}{\partial V^2} \bigg|_{T=T_c,V=V_c} = 0 $