Algorithms/Combinatorics
From charlesreid1
Notes
Knuth AOCP Volume 3 Sorting and Searching
5.1 Combinatorics
Knuth begins talking about sorting by talking about combinatorics and permutations of items.
Start with definition of an inversion:
Let $ a_1 a_2 a_3 \dots a_n $ be a permutation of the integers $ {1 \dots n} $.
If $ i < j $ and $ a_i > a_j $, then $ (a_i, a_j) $ is an inversion.
Inversions are out-of-sorts pairs.
Cramer (1750) introduced inversions - utilized to find determinant.
Can also construct an inversion table:
Let $ b_1 b_2 \dots b_n $ denote the inversion table of $ a_1 a_2 \dots a_n $. Then $ b_j $ is the number of elements to the left of j that are greater than j.
Example of sequence and its inversion table:
5 9 1 8 2 6 4 7 3 2 3 6 4 0 2 2 1 0
$ 0 \leq b_1 \leq n-1, 0 \leq b_2 \leq n-2, \dots, 0 \leq b_{n-1} \leq 1 $
Hall (1956) showed that inversion tables uniquely determine permutations - these make inversion tables alternative representations for different permutations.
Transformation technique: turn counting problems into inversion table problems
Now, suppose we want to count number of elements larger than their successor. (This is the number of j such that $ b_j = n-j $).
Note that this idea is related to nested for loops:
for(int i = 0; i < N; i++ ) {
for(int j = i; j < N; j++) {
We have $ b_j = n - j $
Since we know the probability that b1 equals n-1 is $ P(b_1 = n-1) = \frac{1}{n} $,
and independently the probability that b2 equals n-2 is $ P(b_2 = n-2) = \frac{1}{n-1} $,
and so on, then we can say:
$ \dfrac{1}{n} + \dfrac{1}{n-1} + \dots + 1 = H_{n} $
These are the harmonic numbers.
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