FMM8
From charlesreid1
Friday Morning Math Problem
The Flippant Juror
A 3-person jury has 2 members, each of whom has an independent probability P of making a correct decision. The third juror flips a coin. (Majority rules.)
A 1-person jury has 1 member who has a probability P of making the correct decision.
Which jury has a better probability of making the correct decision?
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The probability of a 3-person jury making a correct decision is the union of two situations (here, Juror 1 and 2 have probability P of being right, while Juror 3 has a 50% probability of being right):
P_{3 correct} = ( P_{juror 1 correct} and P_{juror 3 correct} ) or (P_{juror 2 correct} and P_{juror 3 correct}) Now we know P_{juror 3 correct} is 0.5, we know that "and" translates to multiplication, we know that "or" translates to addition, so: P_{3 correct} = 0.5*P + 0.5*P = P Meanwhile, the 1 person jury has a probability of making a correct decision of: P_{1 correct} = P From this, we can see that the two juries have an equal probability of being correct. |
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