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** Casework within recursion: when constructing a cycle in <math>S_{n+1}</math> from <math>S_n</math>, need to analyze how cycle traverses connections between the <math>S_n</math> copies, which might involve careful casework depending on which corner vertices are entry/exit points
** Casework within recursion: when constructing a cycle in <math>S_{n+1}</math> from <math>S_n</math>, need to analyze how cycle traverses connections between the <math>S_n</math> copies, which might involve careful casework depending on which corner vertices are entry/exit points


==Core Approach==
==Possible Strategy==


1. Precisely define Sierpinsky graph being dealt with
<code>C(C(C(10_000))) mod 13^8</code> indicates you don't compute full values, but instead exploit mathematical properties:


2. Understand its recursive construction
* Periodicity:
 
** check if the sequence C(n) (mod M) becomes periodic at some point.
3. Use mathematical induction or recursive arguemnt to prove existence of Hamiltonian cycles
** If a period P can be found, then C(X) (mod M) = C(X (mod P)) (mod M)
 
** Chinese Remainder Theorem if M is composite, or properties relate to powers of primes (such as 13^8)
4. Leverage recursive structure and symmetry to develop recurrence relation for number of distinct Hamiltonian cycles
 
5. Solve recurrence relation to find formula for count as function of n


* Matrix exponentiation:
** If recurrence C(n) is linear homogeneous recurrence, such as C(n) = a*c(n-1) + b*C(n-2), then it can be solved with matrix exponentiation
** Technique works extremely well with modular arithmetic
** Allows computing C(N) (mod M) even for very large N in O(log N) matrix multiplications


* Fixed points or specific properties:
** Specific property related to C, and modulus 13^8, potentially?
** C(n) (mod M) might converge to a fixed point for large n,
** C(n) (mod M) might simplify greatly if n is a value modulo M,





Revision as of 01:07, 20 April 2025

Problem Statement

A Sierpiński graph of order-1 ($ S_1 $) is an equilateral triangle.

$ S_{n + 1} $ is obtained from $ S_n $ by positioning three copies of $ S_n $ so that every pair of copies has one common corner.

0312_sierpinskyAt.gif

Let $ C(n) $ be the number of cycles that pass exactly once through all the vertices of $S_n$.

For example, $ C(3) = 8 $ because eight such cycles can be drawn on $ S_3 $, as shown below:

0312_sierpinsky8t.gif

It can also be verified that:

$ C(1) = C(2) = 1 $

$ C(5) = 71328803586048 $

$ C(10\,000) \bmod 10^8 = 37652224 $

$ C(10\,000) \bmod 13^8 = 617720485 $

Find $ C(C(C(10\,000))) \bmod 13^8 $

Notes

This problem is asking about Hamiltonian cycles on Sierpinski graphs.

The problem combines elements of graph theory, combinatorics, and fractal geometry.

Key concepts:

  • Graph theory fundamentals
    • Definition of a graph
    • Cycles and paths
    • Hamiltonian cycles (precise definition is important - cycle visiting every vertex precisely once)
    • Graph properties (number of vertices and edges as function of recursion level)
  • Sierpinsky Graphs
    • Recursive construction ($ S_{n+1} $ in terms of $ S_n $)
    • Vertex and edge growth
    • Vertex degrees
  • Hamiltonian Cycle Theory
  • Recursion and mathematical induction
    • Exploiting recursive structure is central principle for Sierpinski graphs
    • Inductive proofs (arguments based on the recursion level n, base case of 0 or 1)
    • Recursive counting: how to construct Hamiltonian cycles in $ S_{n+1} $ from those in $ S_n $, recurrence relation would be a formula for H(n+1) in terms of H(n) (and potentially other related counts), where H(n) is number of hamiltonian cycles in S(n)
  • Combinatorial Counting
    • Recurrence relation may require using standard techniques
    • Symmetry: Sierpinsky graphs possess significant symmetry (rotational/reflectional), so exploiting this symmetry can potentially greatly reduce counting arguments. This looks like counting "real different" cycles, and multiplying by a symmetry factor.
    • Casework within recursion: when constructing a cycle in $ S_{n+1} $ from $ S_n $, need to analyze how cycle traverses connections between the $ S_n $ copies, which might involve careful casework depending on which corner vertices are entry/exit points

Possible Strategy

C(C(C(10_000))) mod 13^8 indicates you don't compute full values, but instead exploit mathematical properties:

  • Periodicity:
    • check if the sequence C(n) (mod M) becomes periodic at some point.
    • If a period P can be found, then C(X) (mod M) = C(X (mod P)) (mod M)
    • Chinese Remainder Theorem if M is composite, or properties relate to powers of primes (such as 13^8)
  • Matrix exponentiation:
    • If recurrence C(n) is linear homogeneous recurrence, such as C(n) = a*c(n-1) + b*C(n-2), then it can be solved with matrix exponentiation
    • Technique works extremely well with modular arithmetic
    • Allows computing C(N) (mod M) even for very large N in O(log N) matrix multiplications
  • Fixed points or specific properties:
    • Specific property related to C, and modulus 13^8, potentially?
    • C(n) (mod M) might converge to a fixed point for large n,
    • C(n) (mod M) might simplify greatly if n is a value modulo M,





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