From charlesreid1

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===conditions===
===conditions===


we know <math>0 < \frac p q < \frac 1 {100}</math>
we know <math>0 < \frac p q < \frac 1 {100}</math>, which implies <math>q > 100p</math>
 
which implies <math>q > 100p</math>


together with the upper bound for q, this provides a range of values of q: <math>100p < q < 10^8</math>
together with the upper bound for q, this provides a range of values of q: <math>100p < q < 10^8</math>

Revision as of 01:27, 16 April 2025

Problem Statement

A best approximation to a real number x for the denominator bound d is a rational number $ \frac r s $ (in reduced form) with $ s \le d $, so that any rational number $ \frac p q $ which is closer to x than $ \frac r s $ has $ q > d $

Usually the best approximation to a real number is uniquely determined for all denominator bounds. However, there are some exceptions, e.g. $ \frac 9 {40} $ has the two best approximations $ \frac 1 4 $ and $ \frac 1 5 $ for the denominator bound 6. We shall call a real number x ambiguous if there is at least one denominator bound for which x possesses two best approximations. Clearly, an ambiguous number is necessarily rational. How many ambiguous numbers $ x=\frac p q, 0 < x < \frac 1 {100} $, are there whose denominator q does not exceed $ 10^8 $?

examples

9/40 is an ambiguous number, with two best approximations 1/4 and 1/5, for a denominator bound of 6 (q < 6)

conditions

we know $ 0 < \frac p q < \frac 1 {100} $, which implies $ q > 100p $

together with the upper bound for q, this provides a range of values of q: $ 100p < q < 10^8 $

Technique

Start with a program that won't scale, and generate intermediate solutions (smaller values of q limit) that we can trust.

Then, introduce optimizations to scale further, and use intermediate solutions to verify optimizations aren't changing answers.

Develop insights about ambiguous numbers in the process.

q < 10,000 is very fast to compute, but q < 1,000,000 can take way, way longer.

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